If tanA = cotB where A and B are acute angles, prove that A + B = 90º.
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Hi ,
Given that tanA = cotB -----( 1 )
we know that cotB = tan ( 90° - B ),
We can write ( 1 ) as
tanA = tan( 90° - B )
If A , B are acute angles , then
A = 90° - B
=> A + B = 90°
I hope this helps you.
: )
Given that tanA = cotB -----( 1 )
we know that cotB = tan ( 90° - B ),
We can write ( 1 ) as
tanA = tan( 90° - B )
If A , B are acute angles , then
A = 90° - B
=> A + B = 90°
I hope this helps you.
: )
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