if tanA = n / n+1 and tanB = 1 / 2n+1 then prove that tan(A+B) = 1
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Step-by-step explanation:
Since tan(A+B)=tanA+tanB/(1-tanAtanB)
Since TanAtanB=n/(n+1)(2n+1)
And tanA+tanB=n/(n+1)+1/(2n+1)
=[n(2n+1)+n+1]/(n+1)(2n+1)
Replacing this in the question, you will get 1
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