if (tana+seca)=l prove that l^2+l/2l=seca
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tanA + secA=l
squaring both sides
tan²A+sec²A=l²
as tan²A=sec²A-1
so,
sec²A-1+sec²A=l²
2sec²A-1=l²
(secA+1)(secA-1)=l²-sec²A
sec²-1=l²-sec²A
as sec²A=1/cos²A
(1-cos²A)/cos²A=(l²cos²A-1)/cos²A
1-cos²A=l²cos²A-1
squaring both sides
tan²A+sec²A=l²
as tan²A=sec²A-1
so,
sec²A-1+sec²A=l²
2sec²A-1=l²
(secA+1)(secA-1)=l²-sec²A
sec²-1=l²-sec²A
as sec²A=1/cos²A
(1-cos²A)/cos²A=(l²cos²A-1)/cos²A
1-cos²A=l²cos²A-1
Sakshishivaye12:
Thank u so much
sorry was not able to complete it , but plz don't rrport it
really sorry
Ok dear I will complete it myself
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