if tanA+secA=m and tanA-secA=n,then prove that mn+1=0
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here is your answer above the attachment .. hope its help
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mansigupta23:
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Answered by
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(tanA+secA)(tanA-secA)+1
(tan^2-sec^2A)+1
-1+1
=0
(tan^2-sec^2A)+1
-1+1
=0
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