Math, asked by harley1110, 14 hours ago

If tanA+sinA=mAnd tan A-SinA=n,show that m^2-n^2=mn

Answers

Answered by bhoomigupta13112009
0

Step-by-step explanation:

= m²-n²=(m+n)(m-n)

= 2tan A. 2sin A= 4 tan A sin A

= 4√(mn) = 4√(tan²-Asin²A)

= 4sin A√(sec²A-1) = 4sin A tan A

= therefore, m²-n²=4√(mn)

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