If tanA + sinA = p and tanA – sinA = q, then 4 tanA sinA=
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-- So, on adding both the equations 2*tanA = p+q
So, tan A = (p+ q)/2
-- On putting tan A values in equation 1,
sin A = (p - q)/2
4 tan A sin A
= 4* (p+q)/2 * (p - q)/2
=p^2 - q^2
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