If tanA.tanB= tan 45°, then find sin (A+B)
Answers
Answered by
5
I think the answer will be be 1.
Take A=30°
B=60°
Take A=30°
B=60°
Answered by
18
Answer:
0
Step-by-step explanation:
tanA.tanB = tan 45 = 1
tan(A+B) = (tanA+tanB)/1-tanAtanB
tan(A+B) = (tanA+tanB)/ 1 - 1 = 0
sin(A+B)/cos(A+B) = 0
sin(A+B) = 0
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