Question

If tanA + tanB = X, then the value of X is

A) (tanA - tanB)/(1 + tanAtanB) B) (tanA + tanB)/(1 - tanAtanB) C) (tanA + tanB)/(1 + tanAtanB) D) (tanA - tanB)/(1 - tanAtanB)

Answer 1

Step-by-step explanation:

tanA+tanB = (sinA/cosA)+(sinB/cosB)

= (sinAcosB + sinBcosA)/(cosAcosB)

= (Sin(A+B))/(cosAcosB)

Therefore

tanA+tanB = (sin(A+B))/(cosAcosB)

Or

we know that

tan(A+B) = (tanA + tanB) /(1-tanAtanB)

tanA+tanB = tan(A+B)(1-tanAtanB)

Answer 2

Answer:

Hey mate here is your answer ⬇️

Option d is your answer....