Question

if tanA=
$\frac{3}{4}$
then find the value of sinA and cosA​

Answer 1

Answer:

$\\\tt cosA =\dfrac{4}{5}$

$\\\tt sinA=\dfrac{3}{5}$

Step-by-step explanation:

Since tan A can also be expressed as $\\\tt \dfrac{Opposite}{adjacent}$ in a triangle

Consider a right angled triangle with  Opposite side to the given angle A of measure 3 units and the adjacent  to that angle be 4 units the y using Pythagoras theorem the hypotaneous must be of 5 units.  

$\\\tt cosA = \dfrac{Adjacent}{Hypotaneous} \\\\\tt = \dfrac{4}{5}$

Similarly,

$\\\tt cosA = \dfrac{Opposite}{Hypotaneous} \\\\\tt = \dfrac{3}{5}$

Answer 2

tan A = 3/4

tan A = opp/adj

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hyp²=opp²+adj²

hyp² = 3² + 4²

hyp² = 9 + 16

hyp² = 25

hyp = √25

hyp = 5

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sin A = opp/hyp

sin A =3/5

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cos A = adj / hyp

cos A = 4/5

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i hope this helps you

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please mark as brainlist answer