Question

If (tan@ + cot@) = 2 then (tan¹³@ + cot¹³@) = ?​

Answer 1

$here \: is \: your \: answer$

tana + cota =2

take square both sides

(tana + cota)? = 22

tan'a + cot?

a +2tana

.cota =4

we Know,

tana =1/cota so, tan? a + cot'a +2 = 4

tan?a + cot?

a = 4 -2 = 2

Answer 2

Answer:

2

Step-by-step explanation:

Tan@+Cot@=2

∴(SIN@/COS@)+(COS@/SIN@)=2

∴(SIN²@+COS²@)/SIN@COS@=2

∴1/SIN@COS@=2

∴SIN@COS@=1/2........<1>

∴TAN∧13@+COT^13@)=(SIN^13@/COS^13@)*(COS^13@/SIN^13@)

∴TAN^13+COT^13=(SIN^26@+COS^26@)/(SIN@COS@)^13

∴[(SIN^2@+COS^2)^13]/SIN@COS@)

=1^13/1/2=1/1/2=2...................ANSWER

OR

WE KNOW THAT TAN45=COT45=1

∴TAKING@=45,

TAN45^13+COT45^13=1^13+1^13=1+1=2....ANSWER