if tanB=1-tanA/1+tanA then find the value of tan(A+B)
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Here is your answer:
(1+tanA)(1+tanB)=2
∴tan(A+B)=
1−tanAtanB
tanA+tanB
........... (1)
Now 1+tanA+tanB+tanAtanB=2
∴tanA+tanB=1−tanAtanB
∴
1−tanAtanB
tanA+tanB
=1 ........ (2)
∴ From (1) & (2)
tan(A+B)=1
∴A+B=
4
π
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Answer:
what?
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