Math, asked by ridham4397, 8 months ago

If tanB=√3 and tanC =1/√3 ,0<B,C<90⁰ ,find the value of Cot(B+C)​

Answers

Answered by kushagragupta3981
2

Answer:

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Answered by Anonymous
1

Answer:

very simple

Step-by-step explanation:

 \tan(b)   =  \sqrt{3}  \\  \tan(b ) =  \tan(60)  \\ b = 60 \\

 \tan(c)  =  \frac{1}{ \sqrt{3} }  \\ c = 30

 \cot(b + c)  =  &gt;  \cot(90)  =  &gt; 0

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