Question

If tanB=5/12,find secB+cosecB, where B is acute angle Please give me the answer first

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Hello friends!

Step-by-step explanation:

We know that, 1-tanB = secB

1-5/12

= (12-5)/12

= 7/12

cosB = (1/secB)

cosB = 12/7

We know that, tanB= sinB/cosB

Therefore, sinB = tanBcosB

sinB = 5/12 × 12/7

sinB = 5/7

We know that, cosecB = 1/sinB

cosecB = 7/5

secB+cosB =7/12 + 7/5

=(35+84)/60

=119/60

= 1(59/60)