Question

If tane =1/2
2sin O + 3 cos 0
4cos 0 + 3sin 0​

Answer 1

Answer:

not sure about the answer

hope that it should be useful for u

Answer 2

Answer:

Step-by-step explanation:

solution:

tan∅=1÷2

tan=p÷b

then,

p=1 and b=2

using pythagoras theorem

h=√p²+b²

   =√1²+2²

  =√1+4

∴h  =√5

now

2sin + 3cos

=2×p÷h+3×b÷h

=2×1÷√5+3×2÷√5

=2÷√5+6÷√5

=8√5÷5