Question

If tane + sine = m and tane - sine = n and also men, then prove that m2 - n2 = 4 mn​

Answer 1

Answer:

$l$

l. h.s: m2-n2

=(tane+sine)^-(tane-sine)^

=tan^e+2tane.sine+sin^e-tan^e+2tane.sine-sin^e

=4tane.sine

r. h. s: 4mn

=4(tane+sine) (tane-sine)

=4{tane(tane-sine) +sine(tane-sine)}

=4(tan^e-tane.sine+sine.tane-sin^e)

=4(tan^e-sin^e)