if tangent 2a=cot(a+60). find the value of a where 2a is an acute angle
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Heya,
Given=>
tan2A = cot(A + 60°)
tanA = cot(90° - A)
therefore,
tan2A = cot(90° - 2A)
So,
cot(90° - 2A) = cot(A + 60°)
Cot will get cancelled both side,
90° - 2A = A + 60°
3A = 30°
A = 10°. ..... Answer
Hope this helps...:)
Given=>
tan2A = cot(A + 60°)
tanA = cot(90° - A)
therefore,
tan2A = cot(90° - 2A)
So,
cot(90° - 2A) = cot(A + 60°)
Cot will get cancelled both side,
90° - 2A = A + 60°
3A = 30°
A = 10°. ..... Answer
Hope this helps...:)
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