Math, asked by jassmeet7709, 1 year ago

If tangent PA and PB form a point 'P' to a circle with centre o are inclined each other at 80 degree.find

Answers

Answered by haridasan85
0

Answer:

Question in complete Pls. Supply

omission

Answered by Anonymous
1

Answer:

In a OPA and OPB

OP=OP (common)

Angle PAO =Angle PBO (90°each )

OA=OB (equal radii)

By RHS criteria

OPA≈ OPB

therefore Angle 1 = Angle 2 (By C. P. C. T)

Angle 1 = Angle 2 = 1/2 of 80

Angle 1 = Angle 2 = 40°

Now , In POA, By ASP

40°+ Angle POA + 90° = 180°

130°+ Angle POA +90°= 180°

Angle POA =180°-130°

Angle POA = 50°

OPTION (A) IS CORRECT :- 50°

hope it is helpful for u

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