Question

If tangenta at p and q meet at t then tp and tq subtend equal angle at focus

Answer 1

Answer:

Let P be the point (at2, 2at1), and Q be the point (at22, 2at2), so that T is the point {at1t2, a(t1 + t2)}.

The perpendicular, TU, from T on this straight -

Similarly TU' has the same numerical value. The angles PST and QST are therefore

and the angles TSP and TSQ are equal, the triangles SPT and STQ are similar, so