Question

if tangential acceleration vector of a speeding up particle at p =3i +4j cap m/s^2 find the theta

Answer 1

Explanation:

30 is answer hope it helps you

Answer 2

The theta θ is 53°.

Given:

p =3i +4j m/s²

To Find:

The thetaθ

Solution:

We know tanθ is the slope in the graph

slope  = y/x    -----(1)

p =3i +4j  here the coefficient of j is the y component and the coefficient of i is the x component.

tan θ = 4/3 from the slope formula given above (1)

θ = tan⁻(4/3)

θ = 53°

Hence, The theta θ is 53°.

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