Question

if tangents ab and ac from a point a to a circle with centre o are inclined to each other at angle of 70, then angle aob is equal to​

Answer 1

Step-by-step explanation:

Given:

TA and TB are tangents to circle O.

∠T=70

o

To find:

∠AOB

Solution:

Tangent and normal at a point on a circle are perpendicular to each other.

∠A=∠B=90

o

Sum of angles of a quadrilateral is 360

o

.

∠A+∠B+∠O+∠T=360

o

90

o

+90

o

+∠O+70

o

=360

o

∠O=110

o

Answer 2

Answer:

Given: TA and TB are tangents to circle O.

∠T=70

To find: ∠AOB

Tangent and normal at a point on a circle are perpendicular to each other.

∠A=∠B=90

Sum of angles of a quadrilateral is 360

∠A+∠B+∠O+∠T=360

90 +90 +∠O+70  =360

∠O=110