if tangents ab and ac from a point a to a circle with centre o are inclined to each other at angle of 70, then angle aob is equal to
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2
Step-by-step explanation:
Given:
TA and TB are tangents to circle O.
∠T=70
o
To find:
∠AOB
Solution:
Tangent and normal at a point on a circle are perpendicular to each other.
∠A=∠B=90
o
Sum of angles of a quadrilateral is 360
o
.
∠A+∠B+∠O+∠T=360
o
90
o
+90
o
+∠O+70
o
=360
o
∠O=110
o
Answered by
2
Answer:
Given: TA and TB are tangents to circle O.
∠T=70
To find: ∠AOB
Tangent and normal at a point on a circle are perpendicular to each other.
∠A=∠B=90
Sum of angles of a quadrilateral is 360
∠A+∠B+∠O+∠T=360
90 +90 +∠O+70 =360
∠O=110
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