Question

If tangents PA and PB from a point P to a circle with a centre O are inclined to each other at an angle of 70 degrees, find /_POA

Answer 1

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hope this helps you

Answer 2

Answer:


Step-by-step explanation:

InAOBP

<OAP+<APB+<PBO+<BOA=360°(sum of all interior angles are 360°)

90°+70°+90°+<BOA=360°

250°+<BOA=360°

360°-250°=<BOA

110°=<BOA

<POA=1/2<BOA

<POA=110/2

<POA=55°

I hope this will help you