Question

If tangents PA and PB from a point P to a circle with center O are inclined to each other at angle of 80° , then angle POA is equal to:-
a. 50°
b. 60°
c. 70°
d. 80°



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don't post any irravelent answer....​

Answer 1

Answer:

A = 50°

Step-by-step explanation:

If you have figure of question then:

In triangle POA:

angleOAP = 90° ( THEOREM )

angle APO=40° ( CONSIDER LINE OP AS BISECTOR 80/2 )

SO angle POA= 180-130

= 50°

Answer 2

Answer:

A = 50°

Step-by-step explanation:

If you have figure of question then:

In triangle POA:

angleOAP = 90° ( THEOREM )

angle APO=40° ( CONSIDER LINE OP AS BISECTOR 80/2 )

SO angle POA= 180-130

= 50°

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