If tangents PA and PB touches the circle at A and B and the radius of circle is 5cm and OP=13 find AB
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refer the attachment hope its help u
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Answer:
PA and PB are tangent ⇒∠OAP=90
and ∠OBP=90
OA and OB are the radius
OA=OB=5cm
OP=13cm
In ΔOAP
OA is perpendicular to AP, as in a circle the radius and the tangent are perpendicular at a point on the circle.
∴ OA2 +AP2 =OP2
⇒AP2 = 169 - 25
⇒AP=12cm
Similarly in ΔOBP
OB2 +BP2 =OP 2
⇒BP=12cm
∴ Perimeter of OAPB=OA+AP+PB+OB=5+12+12+5
=10+24=34cm
Step-by-step explanation:
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