if tangle ABC nd tangle DEF are similar such that 2AB =DE nd BC= 8 cm than EF =.....plz give me ans
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Answered by
1
As, triangle ABC and DEF r similar ..... and DE = 2AB and BC = 8 cm .........
then according to sides theorem :-
AB / DE = BC / EF
AB / 2AB = BC / EF [as DE = 2AB]
1 / 2 = BC / EF
EF = 2BC
EF = 2 * 8 = 16 cm
then according to sides theorem :-
AB / DE = BC / EF
AB / 2AB = BC / EF [as DE = 2AB]
1 / 2 = BC / EF
EF = 2BC
EF = 2 * 8 = 16 cm
prachi153:
But in my text book it is given 4 cm...
then thats wrong i think.
Oh ok tnx...
my pleasure:)
Hm
/^*));;
Hm✌
Answered by
4
EF=16..
Becoz,BC/EF=1/2
8/EF=1/2
HENCE,,, EF=16cnm
Becoz,BC/EF=1/2
8/EF=1/2
HENCE,,, EF=16cnm
thanq prachi.
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