Question

if tanO=3/4 find secO and cosO ?​

Answer 1

Given:

tan ø = 3/4

To find:

Sec ø and Cos ø

Solution:

We know that Tan ø = Opposite/ Adjacent

Tan ø = 3/4

Let the numbers be k.

Now, Tan ø = 3k/4k

So, Opposite side = 3k and Adjacent side = 4k.

Hypotenuse = 5k

→ Sec ø = Hypotenuse/Adjacent = 5k/4k = 5/4

→ Cos ø = 1/sec ø = Adjacent/Hypotenuse = 4k/5k = 4/5

Conclusion:

Therefore, Sec ø = 5/4 and Cos ø = 4/5

Extra information:

All trigonometric ratios:

• Sin ø = Opposite/Hypotenuse = 1/cosec ø
• Cos ø = Adjacent/Hypotenuse = 1/sec ø
• Tan ø = Opposite/Adjacent = 1/cot ø
• Sec ø = Hypotenuse/Adjacent = 1/cos ø
• Cosec ø = Hypotenuse/Opposite = 1/sin ø
• Cot ø = Adjacent/Opposite = 1/tan ø