Question

If tano = 3/4 find the values of seco and coso​

Answer 1

Answer:

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SecØ +TanØ=4

SecØ= 4-TanØ

squaring both sides

Sec²Ø= 16 + Tan²Ø- 8 TanØ

1+Tan²Ø=16 + Tan²Ø- 8 TanØ

we get 8Tan Ø= 15

TanØ=15/8

Tan²Ø= 225/64

Sec²Ø= 1+Tan²Ø

Sec²Ø= 289/64

SecØ =17/8

So CosØ=8/17

Sin²Ø=1-Cos²Ø = 1-64/289

Sin²Ø= 225/289

SinØ= 15/17

Cos Ø= 8/17 and Sin Ø= 15/17

Answer 2

5/4 and 4/5

Step-by-step explanation:

1+tan^2=sec^2

sec=5/4

now cos=1/sec

cos=4/5