Question

If tano = 8/5 find the other trignometre ratios​

Answer 1

Step-by-step explanation:

Given, $\tan \theta = \frac{8}{5} = \frac{p}{b}$

So, p = 8, b = 5 and h = ?

Where p= perpendicular, b= base and h=height

By using Pythagoras theorem,

$\boxed{h=\sqrt{p^{2}+b^{2} } }$

$h = \sqrt{(8)^{2}+ (5)^{2} }$

$h = \sqrt{64+25}$

$\therefore h= \sqrt{89}$

Hence,

$sin \theta = \frac{p}{h} = \frac{8}{\sqrt{89}}$

$\cos \theta = \frac{b}{h} = \frac{5}{\sqrt{89}}$

$cosec \theta = \frac{h}{p} = \frac{\sqrt{89}}{8}$

$sec \theta = \frac{h}{b} =\frac{\sqrt{89}}{5}$

$cot \theta = \frac{b}{p} = \frac{5}{8}$

Answer 2

Answer:

Step-by-step explanation: