Question

If tano =
then sin o is equal to
3
4
-4
4
(2)
or
5
5
5
-(1) but not
(3) 23 but not in a
(4) None of these​

Answer 1

Answer:

given, tanthita =-4/5

Step-by-step explanation:

so, we know that ,,tanthita =p/b

and sinthita=p/h

so from Pythagoreans pramey, h=√b2+√p2

after solution h=5

so, Sinthita=p/h=4/5.ans

Answer 2

AnsWer :

2 ) - 4 / 5 or 4 / 5.

QuestioN :

$\tt If \: tan \,\theta = \dfrac{ - 4}{3} then, \: Sin\, \theta \: Equal \: to$

SolutioN :

$\tt If \: tan \,\theta = \dfrac{ - 4}{3} then, \: Sin\, \theta \: Equal \: to$

We know,

$\tt \dagger \: \: \: \: \: \boxed{\tt1 + tan^2\,\theta = Sec^2\,\theta}$

So,

$\tt : \implies1 + tan^2\,\theta = Sec^2\,\theta$

$\tt : \implies1 + \bigg (\dfrac{ - 4}{3} \bigg)^{2} = Sec^2\,\theta$

$\tt : \implies1 + \dfrac{ 16}{9} = Sec^2\,\theta$

$\tt : \implies \dfrac{ 9+ 16}{9} = Sec^2\,\theta$

$\tt : \implies \dfrac{ 25}{9} = Sec^2\,\theta$

$\tt : \implies Sec^2\,\theta = \dfrac{25}{9}$

$\tt : \implies Sec\,\theta = \sqrt{ \dfrac{25}{9} }$

$\tt : \implies Sec\,\theta = \pm \dfrac{5}{3}$

$\rule{200}3$

☛ We have,

• Sec θ = 5 / 3 or - 5 / 3.
• tan θ = - 4 / 3.

$\tt \bullet \: \: \: \: \: Sec\,\theta = \dfrac{Hypotenuse}{Base}$

$\tt \bullet \: \: \: \: \: tan\,\theta = \dfrac{Perpendicular}{Base}$

☛ Where as,

• Hypentenus = 5 or - 5.
• Perpendicular = - 4.
• Base = 3.

$\rule{200}3$

☛ If We take,

• Sec θ = 5 / 3.

$\tt \bullet \: \: \: \: \: Sin\,\theta = \dfrac{Perpendicular}{Hypentenus}$

$\tt \bullet \: \: \: \: \: Sin\,\theta = \dfrac{ - 4}{5}$

☛ If We take,

• Sec θ = - 5 / 3.

$\tt \bullet \: \: \: \: \: Sin\,\theta = \dfrac{ - 4}{ - 5}$

$\tt \bullet \: \: \: \: \: Sin\,\theta = \dfrac{ 4}{5}$

✡ Therefore, the correct option is 2 ) - 4 / 5 or 4 / 5.