Question

❥❥❥❥❥❥❥❥❥❥❥❥❥❥❥❥❥❥ If tanØ = 1
then,find the value of sinØ + cosØ / secØ + cosecØ
​

Answer 1

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Given:-

$tan \: \theta = 1$

$tan \: \theta = tan \: 45$

So,

$=> \theta = 45$

To Find:-

$sinØ + cosØ / secØ + cosecØ$

Solution:-

$sinØ + cosØ / secØ + cosecØ$

$= > sin \: 45 + \frac{cos \: 45}{s ec\: 45} + cosec \: 45$

$=> \frac{1}{ \sqrt{2} } + \frac{ \frac{1}{ \sqrt{2} } }{ \sqrt{2} } + \sqrt{2}$

$= > \frac{1}{ \sqrt{2} } + \frac{1}{2} + \sqrt{2}$

$= > \frac{ \sqrt{2} }{2} + \frac{1}{2} + \frac{ 2 \sqrt{2} }{2}$

$= > \frac{ { \sqrt{2} + 1 + 2 \sqrt{2} } }{2}$

$= > \frac{3 \sqrt{2} + 1}{2}$

Answer 2

Answer:

$\answer$

This is correct answer