If tanø+cotø=2, show that tan⁷ø+cot⁷ø=2
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Hi there !!
Ø = A ( I am taking A instead of thetha)
It is given that, tanA+ CotA= 2
TanA + 1/tanA = 2 {We now that cotA =1/tanA)
Now, tan²A+ 1=2tanA
Tan²A-2tanA+1=0
(Let tanA be x so it will become quadratic equation)
TanA + 1/tanA = 2
{We now that cotA =1/tanA)
Now,
tan²A+ 1=2tanA
Tan²A-2tanA+1=0(Let tanA be x so it will become quadratic equation)
x²-2x+1=0
x²-x-x+1=0
x(x-1) -1(x-1)
(x-1)²=0 or x=1
Means, tanA =1 Value of tan^7+cot^7
(1)^7+(1/1)^7= 2
Thankyou :)
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