Question

if tanQ=9/40 then SinQ and cosQ​

Answer 1

Answer:

• SinA = 9/41
• CosA = 41/40

Step-by-step explanation:

Given that,

• tanA = 9/40

We know,

tanA = sinA/cosA

➡ 9/40 = sinA/cosA

➡ sinA = 9/40cosA

Applying identities,

sin²A + cos²A = 1

➡ (9/40cosA)² + cos²A = 1

➡ 81/1600 cos²A + cos²A = 1

➡ 1600cos²A + 81cos²A/1600 = 1

➡ 1681cos²A/1600 = 1

➡ cosA = √1681/1600

➡ cosA = 41/40

Now,

➡ sinA = 9/40cosA

➡ sinA = 9/40 × 41/40

➡ sinA = 9/40 × 40/41

➡ sinA = 9/41