Question

if tanQ+secQ=5/2,then find sec Q

Answer 1

Answer:

29/20

Step-by-step explanation:

given $sec^{2} Q-tan^{2} Q=1\\(secQ+tanQ)(secQ-tanQ)=1\\\frac{5}{2}(secQ-tanQ)=1\\ (secQ-tanQ)=\frac{2}{5}\\ given (secQ+tanQ)=\frac{5}{2} \\add the above we get 2secQ=\frac{5}{2} +\frac{2}{5} \\2secQ=\frac{29}{10}\\ secQ=\frac{29}{20}$