Question

if tanteta=√3 where teta is acute then find the value of 1+cos teta​

Answer 1

Answer:

tanteta=√3.

teta=60°.

1+costeta=1+cos60°

=1+1/2

=3/2

Answer 2

Step-by-step explanation:

............

$\tan(theta) = \sqrt{3} \\ \tan(theta) = \frac{perpendicular}{base} = \frac{ \sqrt{3} }{1} \\ perpendicuar = \sqrt{3} .base =1. hypotaneous = 2 \\ \cos(theta) = \frac{b}{h} \\ \cos( + 1 ) = \frac{1}{2} + \frac{1}{1} \\ = \frac{1 + 2}{2} \\ \frac{3}{2}$