Question

if tantheta =3 then (4 sin theta- cos theta/4sintheta + costheta) is equal to​

Answer 1

Answer:

correct answer is 11/13

Answer 2

Solution :-

given that,

→ tan θ = 3

So,

→ tan θ = 3/1 = P/B

then,

→ H = √(P² + B²) { By pythagoras theorem }

→ H = √(3² + 1²) = √(10)

then,

→ sin θ = P/H = 3/√10

→ cos θ = B/H = 1/√10

putting both values we get,

→ (4•sin θ - cos θ) ÷ (4•sin θ + cos θ)

→ {4•(3/√10) - (1/√10)} ÷ {4•(3/√10) + (1/√10)}

→ {(12/√10) - (1/√10)} ÷ {(12/√10) + (1/√10)}

→ (11/√10) ÷ (13/√10)

→ (11/√10) × (√10/13)

→ (11/13) (Ans.)

Learn more :-

It sino + tano = m

tano - sino an

Then express the

values of m²-n² in terms

of M and N

https://brainly.in/question/13926306

tanA/(1-cotA) + cotA/(1-tanA)

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