Math, asked by anwesha2810, 1 year ago

If tanthita = 20/21 show that 1-sin thita +cos thita /1+sin thita +cos thita

Answers

Answered by Anonymous
1
HI !

tanθ = 20/21 = opposite side(o)/adjacent side(a)

hypotenuse = h = o² + a²

Let , o = 20k  and a = 21k

h² = (20k)² + (21k)²
   = 841k²

h = 29 k

sinθ = o/h 
        = 20k/29k
        =20/29

cos
θ = a/h 
         = 21k/29k
        = 21/29

1 - sin
θ + cosθ ÷ 1 + sinθ + cosθ

= {1 - 20/29 + 21/29 / 1 } 
÷ {1 + 20/29 + 21/29}

= {29/29 - 20/29 + 21/29)
 ÷ {29/29+20/29+21/29}

= {29 - 20 + 21/29} 
÷ {29+20+21/29}

= 30/29 
÷  70/29

29 gets cancelled on both denominator and numerator.

= 30/70

= 3/7


Answered by TheLifeRacer
0
Hope it help you .

@rajukumar.◆◆◆◆◆◆◆●●●●●●●
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