If tanx =2/3,tan y=1/5, then what is x+y
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Solution :
Given tanx = 2/3 --- ( 1 )
tany = 1/5 ----( 2 )
Now ,
tan( x + y )
= [ tan x + tan y ]/( 1 - tanx * tan y )
= [ 2/3 + 1/5 ]/[ 1 - ( 2/3 )( 1/5 ) ]
= ( 10 + 3 )/( 15 - 2 )
= 13/13
= 1
Therefore ,
tan ( x + y ) = tan 45°
=> x + y = 45°
•••••
Given tanx = 2/3 --- ( 1 )
tany = 1/5 ----( 2 )
Now ,
tan( x + y )
= [ tan x + tan y ]/( 1 - tanx * tan y )
= [ 2/3 + 1/5 ]/[ 1 - ( 2/3 )( 1/5 ) ]
= ( 10 + 3 )/( 15 - 2 )
= 13/13
= 1
Therefore ,
tan ( x + y ) = tan 45°
=> x + y = 45°
•••••
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