if tanx=3/4 and x lies in 3rd quadrant ,find sinx
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According to the problem given ,
tanx lies in 3rd quadrant .
tanx = 3/4 [ given ]
In ∆OAB ,
<A = 90°
By Phythogarian theorem ,
OB² = OA² + AB²
= ( -4 )² + (-3 )²
= 16 + 9
= 25
= 5²
OB = 5
Now ,
sinx = AB/OB
= -3/5
••••
tanx lies in 3rd quadrant .
tanx = 3/4 [ given ]
In ∆OAB ,
<A = 90°
By Phythogarian theorem ,
OB² = OA² + AB²
= ( -4 )² + (-3 )²
= 16 + 9
= 25
= 5²
OB = 5
Now ,
sinx = AB/OB
= -3/5
••••
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