if tanx=-4/3and x is not in the second quadrant then find 5 sin x+10cos x+9sec x+16cosec x+4cotx
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since tan x = -4/3 = P/B
therefore by Pythagoras theorem,
hypotenuse = 5
therefore,
=5 sinx + 10 cosx + 9 secx + 16 cosecx + 4 cotx
=(5×-4/5)+(10×3/5)+(9×5/3)+(16×-5/4)+(4×-3/4)
= -4+6+15-20-3
= -27+21
= -6 answer
since x is not in second quadrant therefore it will be in third quadrant.
therefore by Pythagoras theorem,
hypotenuse = 5
therefore,
=5 sinx + 10 cosx + 9 secx + 16 cosecx + 4 cotx
=(5×-4/5)+(10×3/5)+(9×5/3)+(16×-5/4)+(4×-3/4)
= -4+6+15-20-3
= -27+21
= -6 answer
since x is not in second quadrant therefore it will be in third quadrant.
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