If tanx+4/tanx=5,find sinx and cosx
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tan^2 x - 5 tan x + 4 = 0
Could be factored into
(tan x - 4) (tan x -1) = 0
This implies that tan x = 4 or tan x = 1
If tan x = 4 then sec^2 x = 1 + tan^2 x = 1 + 16 = 17
OR cos^2 x = 1/17
So cos x = ± 1/√17 =====> sin x = ± 4/√17 since we need sin^2 x + cos^2 x = 1
And if tan x = 1 then cos x = ± 1/√2 ===> sin x = ± 1/√2.
sasi2418:
How did you get into the first expression
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hey mate ur answer is in the attachment
hopes it helps you...
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