Question

If tanX=5/12 find secX​

Answer 1

Answer:

tanx= 5/12 ........ given

1 + tan²x= sec²x..... identity

1 +5/12(square) =sec²x

1+25/144=sec²x

144+25/144=sec²x

169/144=sec²x

secx=13/12

Answer 2

Answer:

$tanx = \frac{5}{12} \\ {tan}^{2}x = \frac{25}{144} \\ 1 + {tan}^{2} x = {sec}^{2} x \\ 1 + \frac{25}{144} = {sec}^{2} x \\ \frac{144 + 25}{144} = {sec}^{2} x \\ \frac{169}{144} = {sec}^{2} x \\ {sec} x = \frac{13}{12}$

hope it helps you :)