Math, asked by priyanshu2338, 1 year ago

if tanx=5/12 than cos2x

Answers

Answered by bigppboi
3
tanx= 5/12

tan2x=25/144

sec2x=tan2x+1

sec2x= 25/144+1

sec2x=25+144/144
sec2x= 169/144
secx=13/12

secx=1/cosx
cosx=12/13
cos2x=144/169
Answered by 23528
1

tanx= 5/12

tan2x=25/144

sec2x=tan2x+1

sec2x= 25/144+1

sec2x=25+144/144

sec2x= 169/144

secx=13/12

secx=1/cosx

cosx=12/13

cos2x=144/169


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