Question

if tanx+cotx=3 then find the value of tan^2 x+cot^2 x

Answer 1

tan^2x+cot^2x=(tanx+cotx)^2-2tanx.cotx
=9-2tanx.1/tanx
=9-2
=7

hope it helps u dear ❤ ❤

Answer 2

Hey Kartik,

Here we go,


Given:
$\tan(x) + \cot(x) = 3$

Let's square both side,
${( \tan(x) + \cot(x)) }^{2} = {3}^{2}$

${ \tan}^{2} x + { \cot }^{2}x + 2 (\tan \: x)( \cot \: x ) = 9 \\ \\ { \tan}^{2} x + { \cot }^{2}x + 2 = 9 \\ \\ { \tan}^{2} x + { \cot }^{2}x = 7$

Therefore, the required answer is 7.