Question

if tanx+secx=2-root 3 than x=?

Answer 1

secx = (2-√3) - tanx
squaring both sides
=> (secx)^2 = (2-√3)^2 +(tanx)^2 - 2(2-√3) tanx
=> 1+(tanx)^2 = 7 - 4√3 + (tanx)^2 - 2(2- √3)tanx
=> 2(2-√3)tanx = 7-4√3 -1
=> tanx = (6-4√3) / 2(2-√3)
=>tanx = (3-2√3)/(2-√3)
=>tanx = (3-2√3)(2+√3) / (2-√3)(2+√3)
=> tanx = (6+3√3 -4√3 -6) / (4-3)
=> tanx = 3√3 -4√3 = -√3
hence,
x = - 60°
______________
Hope it helps.... if any queries plzz comment or feel free to inbox me