Math, asked by husaindanish488, 4 months ago

If tap A and fill 2/5 of a tank in 12 hours and tap B can fill 1/6 of a tank in 6 hours how long will it take to fill the tank completely if both the taps are opened together.
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Answers

Answered by rj750019
0

Answer:

16.6hr

Step-by-step explanation:

for 1 hr TAp A can fill = 1/3

for 2/5 of a tank can fill = 12hr

tap b will fill in 1/3 in = 1hour

time taken to complete tank = 30 ×36 / 30 + 36 =

= 16.6hr

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