Question

If tap A can fill a tank in 15 h, tap B in 24 h and tap C can empty the tank in 30 h, how long
after all of them are opened together will the tank be full?​

Answer 1

Answer:

Tap A's is one hour work=1/15

Tap B's is one hour work=1/24

Tap C's is one hour work=1/30

A/Q

(1/15)+(1/24)-(1/30)

therefore ANS is 800 minutes or 13 hours and 20 minutes

Answer 2

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal{\bf{{\underline{\underline{\huge\mathcal{...Answer...}}}}}}$

$\underline{\large\mathcal\red{solution}}$

tap A can fill a tank in 15 h

in 1 hour it can fill=1/15 of the tank

, tap B in 24 h

in 1 hour it can fill =1/24of the tank

tap C can empty the tank in 30 h

in 1 hour it can empty =1/30 of the tank

therefore if they opened togethrly then

in 1 hour they will fill

$\frac{1}{15} + \frac{1}{24} - \frac{1}{30} \\ = \frac{1}{30} + \frac{1}{24} \\ = \frac{24 + 30}{30 \times 24} \\ = \frac{3}{40}$

so to fill the tank they will take...=40/3 hrs

=13.33 hr

$\large\mathcal\red{hope\: this \: helps \:you......}$