Question

If temp. Of black body is inc. From 300 k to 600k how does rate of emission change?

Answer 1

I can't understand the qustion

Answer 2

Answer:

Energy Emitted = Epsilon x Sigma x T4

Epsilon = emissivity of the body emitting radiation

Sigma = Stefan Boltzmann constant = 5.67 x 10-8 W m-2 K-4

T = Temperature (K)

So we have:

Epsilon =1 - because it is a black body

T = 6000 K

Energy emitted = [1] [5.67 x 10-8 W m-2 K-4] [ 6000 K]4

= 73,483,200 W m-2

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Explanation:

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