Question

If temperature of 4 kg of material of specific heat capacity 300 J/kg C from 200C to 300C. Find heat

received​

Answer 1

Answer:

The heat received by the material is 120 kJ.

Explanation:

We have given that,

• Mass of material ( m ) = 4 kg
• Specific capacity of material ( c ) = 300 J/kg °C
• Final temperature of material ( T₂ ) = 300° C
• Initial temperature of material ( T₁ ) = 200° C

We have to find the amount of heat received by the material.

Now, we know that,

Heat received by an object is given by

$\displaystyle{\pink{\sf\:Q\:=\:m\:\times\:c\:\times\:\Delta\:T\:}}$

Where,

$\displaystyle{\bullet\sf\:Q\:=\:Heat\:received}$

$\displaystyle{\bullet\sf\:m\:=\:Mass\:of\:object}$

$\displaystyle{\bullet\sf\:c\:=\:Specific\:heat\:capacity}$

$\displaystyle{\bullet\sf\:\Delta\:T\:=\:Change\:in\:temperature\:(\:T_2\:-\:T_1\:)}$

Now,

$\displaystyle{\sf\:Q\:=\:m\:\times\:c\:\times\:\Delta\:T}$

$\displaystyle{\implies\sf\:Q\:=\:4\:kg\:\times\:300\:J\:/\:kg\:^{\circ}C\:\times\:(\:T_2\:-\:T_1\:)\:^{\circ}C}$

$\displaystyle{\implies\sf\:Q\:=\:4\:\cancel{kg}\:\times\:300\:\dfrac{J}{\cancel{kg}\:\cancel{^{\circ}C}}\:\times\:(\:300\:-\:200\:)\:\cancel{^{\circ}C}}$

$\displaystyle{\implies\sf\:Q\:=\:4\:\times\:300\:\times\:100\:J}$

$\displaystyle{\implies\sf\:Q\:=\:1200\:\times\:100\:J}$

$\displaystyle{\implies\sf\:Q\:=\:120000\:J\:}$

$\displaystyle{\implies\sf\:Q\:=\:\dfrac{120\cancel{000}}{1\cancel{000}}\:kJ}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:Q\:=\:120\:kJ}}}}$

∴ The heat received by the material is 120 kJ.

Answer 2

Answer:

Given :-

Mass = 4 kg

Initial temperature = 200⁰ C

Final temperature = 300⁰ C

Heat capacity = 30 J/kg

Need to find :-

Heat recived

Solution :-

At first we need to find Change in temperature

$\bf Change_{(temperature)} = Temperature_{(Final)} - Temperature_{(Initial)}$

Change = 300 - 200

Change = 100⁰ C

Now,

$\bf \red{Q = mcT}$

Where

Q = Heat received

m = mass

c = capacity

T = Temperature

$\sf \: Q = 4 \times 300 \times 100$

$\sf \: Q = 1200 \times 100$

$\sf \: Q = 120000$

Now

1000 J = 1 kJ

120000 J = 1,20,000/1000 = 120 kJ