if temperature of water in 1st beaker is 90 degrees and temperature of water in 2nd beaker is 60 degrees and if the water in two beakers are poured in a large beaker then what will be the temperature of water in the large beaker [please mention the formula also]
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Answer:
hope it helps
Explanation:
Mass of water at 90
o
C=100gm
=100×10
−3
kg
Mass of water at 20
o
C=600gm
=600×10
−3
kg
From calorimetery
m
1
s
1
t
1
+m
2
s
2
t
2
=(m
1
+m
2
)s.T
∵s
1
t
1
+s
2
t
2
=st
[where, T is temperature of mixture].
100×10
−3
×1×90+600×10
−3
×1×20
=(100+600)×10
−3
×1×T
T=
700×10
−3
100×10
−3
×90+600×10
−3
×20
=
700×10
−3
(900+12000)×10
−3
=
700
21000
=30
o
C.
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