If temperature remains constant and the current through a resistor is doubled then the increase in power dissipated will be ( pl explain how) options are.
@ 50%. @100%. @200%. @400%
Answers
Answered by
7
as ve know that
V=IR
at cont temp/ pressure
ohms law is obeyed in this circuit
P=IR2 ........ (ii)
so as per ques. current doubles, hence power will also increase simonteniously so. from eq.. (ii)
hence 100%
V=IR
at cont temp/ pressure
ohms law is obeyed in this circuit
P=IR2 ........ (ii)
so as per ques. current doubles, hence power will also increase simonteniously so. from eq.. (ii)
hence 100%
Answered by
3
Answer:
Explanation:
400%
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