Question

if Temple top of height 75 metre from the top if someone is trying to throw rope on the ground at some distance with angle of elevation 45 degree find the distance of rope and bass of temple​

Answer 1

Answer:

Let AB be the height of the temple and P and Q are the two men on either side of the temple.

Given that,

AB=30 m, ∠APB=30

∘

,∠AQB=60

∘

In △ABP,

tan(∠APB)=

PB

AB

tan30

∘

=

PB

30 m

PB=30

3

m

In △ABP,

tan(∠AQB)=

QB

AB

tan60

∘

=

QB

30 m

QB=

3

m

30

QB=10

3

m

Now, PQ=PB+QB=30

3

m+10

3

m

So, PQ=40

3

m

Therefore, distance between two men, i.e. PQ=40

3

m